探案拍档第四季 （2024）
状态：全3集
类型：剧情 悬疑 犯罪 欧美剧
导演：Khurrum Sultan
主演：杰森·沃特金斯 塔拉·戈维亚
制片国家/地区：英国
简介：2024年Khurrum Sultan执导的英国电视剧《探案拍档第四季》讲述
FilminghasbegunonthefourthseriesofpopularBath-base
FilminghasbegunonthefourthseriesofpopularBath-baseddetectivedramaMcDonald&Dodds,starringTalaGouveiaandBAFTAaward-winnerJasonWatkins.Comprisingthreefeaturelengthfilms(3x120),theguestcastforthefirststoryincludesTobyStephens(LostInSpace),singer/songwriterPixieLott(TheVoiceKids),LydiaLeonard(GentlemanJack),DanielLapaine(Catastrophe),DipoOla(Landscapers),JohnGordonSinclair(Gregory’sGirl)andAceBhatti(LineofDuty).Inthisfirstfilm,McDonaldandDoddsbegintoinvestigatewhenamiddle-agedwomanisfoundshotdeadinarentedflat.Thekillerhasremovedallcluestoheridentity,butDNArevealsshewentmissingover35yearsago.Wherehasshebeenallthoseyears?Andwhowith?ReturningtothecastthisseriesareClaireSkinner(Outnumbered)whoplaysChiefSuperintendentOrmondandCharlieChambers(EastEnders)whoplaysDCGoldie.BhavikC.Pankhania(WorldOnFire)joinsthelineupasDCLee.TheserieshasbeencommissionedforITVbyPollyHillandHuwKennairJonesandwillbeproducedbyJoeShrubb.ExecutiveproducersareRobertMurphy,DamienTimmerandCharlotteWebber.ThefirstfilmiswrittenbyRobertMurphyanddirectedbyKhurrumM.Sultan.HuwKennairJonessaid:“We’rethrilledtobereturningtothebeautifulcityofBathformoreoriginalandinventivecrimesforMcDonaldandDoddstosolve.Andit’sgreattobeworkingwithMammothScreen,RobertMurphyandTalaandJasononceagainonwhatpromisestobeanotherbrilliantseries.”McDonald&DoddsisproducedbyleadingindependentproductioncompanyMammothScreenandcreatedbyRobertMurphy.ThepreviousthreeseriesareavailabletoviewviastreamingplatformsITVXintheUKandBritboxinNorthAmericaandAustralia.ITVStudioswilldistributethedramainternationally.MammothScreenisoneoftheUK’sleadingproductioncompanies.ShowsincludeTheRapture,MurderIsEasy,GrimeKids,WorldOnFire(seriesoneandtwo),Noughts+Crosses(seriesoneandtwo)andTheSerpentfortheBBC,CodeofSilence,TheTower(seriesoneandtwo),TomJones,Endeavour(seriesonetonine)andWhyDidn’tTheyAskEvansforITV.MammothScreenisanITVStudiosCompany.
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